0=2x^2+10x-1128

Solution for 0=2x^2+10x-1128 equation:

0=2x^2+10x-1128

We move all terms to the left:

0-(2x^2+10x-1128)=0

We add all the numbers together, and all the variables

-(2x^2+10x-1128)=0

We get rid of parentheses

-2x^2-10x+1128=0

a = -2; b = -10; c = +1128;
Δ = b2-4ac
Δ = -102-4·(-2)·1128
Δ = 9124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9124}=\sqrt{4*2281}=\sqrt{4}*\sqrt{2281}=2\sqrt{2281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{2281}}{2*-2}=\frac{10-2\sqrt{2281}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{2281}}{2*-2}=\frac{10+2\sqrt{2281}}{-4}
$